Question 37

In the following question, fill in the blanks to make the statements true.

$5^{5} \times 5^{- 5}$ =

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Solution

Using law of exponents,
$a^{m} \times a^{n} = (a)^{m + n} ∴ 5^{5} \times 5^{- 5} = (5)^{5 + (- 5)} = (5)^{0} = 1$
Hence, $5^{5} \times 5^{- 5} = 1$

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