Question

Question 39(ii)
A die has its six faces marked 0,1,1,1,6,6. Two such dice are thrown together and the total score is recorded.
What is the probability of getting a total of 7?

Answer 1

Let E = Event of getting a sum 7
={(1,6),(1,6),(1,6),(1,6),(1,6),(1,6),(6,1),(6,1),(6,1),(6,1),(6,1),(6,1)}
$=n\left(E\right)=12$
$P\left(E\right)=\frac{n\left(E\right)}{n\left(S\right)}=\frac{12}{36}=\frac{1}{3}$