Question 4(c)

Complete the table and by inspection of the table find the solution to the equation $\frac{z}{3} = 4.$

$\begin{matrix} z & 8 & 9 & 10 & 11 & 12 & 13 & 14 & 15 & 16 & \dots & \dots & \dots & \dots \frac{z}{3} & 2 \frac{2}{3} & 3 & 3 \frac{1}{3} & \dots & \dots & \dots & \dots & \dots & \dots & \dots & \dots & \dots & \dots \end{matrix}$

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Solution

$\begin{matrix} z & 8 & 9 & 10 & 11 & 12 & 13 & 14 & 15 & 16 & 17 & 18 & 19 & 20 \frac{z}{3} & 2 \frac{2}{3} & 3 & 3 \frac{1}{3} & 3 \frac{2}{3} & 4 & 4 \frac{1}{3} & 4 \frac{2}{3} & 5 & 5 \frac{1}{3} & 5 \frac{2}{3} & 6 & 6 \frac{1}{3} & 6 \frac{2}{3} \end{matrix}$

The given equation is $\frac{z}{3} = 4.$

By analysing the table above, we can understand that only z = 12 satisfies the given equation.

$∴ z = 12$ is the solution.

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Question 4(d)

Complete the table and by inspection of the table find the solution to the equation m - 7 = 3.

$\begin{matrix} m & 5 & 6 & 7 & 8 & 9 & 10 & 11 & 12 & 13 & \dots & \dots m - 7 & \dots & \dots & \dots & \dots & \dots & \dots & \dots & \dots & \dots & \dots & \dots \end{matrix}$

Question 4(b)

Complete the table and by inspection of the table find the solution to the equation 5t = 35.

$\begin{matrix} t & 3 & 4 & 5 & 6 & 7 & 8 & 9 & 10 & 11 & \dots & \dots & \dots & \dots & \dots 5 t & \dots & \dots & \dots & \dots & \dots & \dots & \dots & \dots & \dots & \dots & \dots & \dots & \dots & \dots \end{matrix}$

Question 4(a)

Complete the table and by inspection of the table find the solution to the equation.

m+ 10 =16

$\begin{matrix} m & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 & 9 & 10 & \dots & \dots & \dots m + 10 & \dots & \dots & \dots & \dots & \dots & \dots & \dots & \dots & \dots & \dots & \dots & \dots & \dots \end{matrix}$

Complete the table and by inspection of the table find the solution to the equation.

$m + 10 = 16$

Question 4(c)

Complete the table and by inspection of the table find the solution to the equation $\frac{z}{3} = 4.$

$\begin{matrix} z & 8 & 9 & 10 & 11 & 12 & 13 & 14 & 15 & 16 & \dots & \dots & \dots & \dots \frac{z}{3} & 2 \frac{2}{3} & 3 & 3 \frac{1}{3} & \dots & \dots & \dots & \dots & \dots & \dots & \dots & \dots & \dots & \dots \end{matrix}$

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Addition of Integers by Forming Pairs

Standard VI Mathematics

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Question 4(c) Complete the table and by inspection of the table find the solution to the equation z3=4. z8910111213141516⋯⋯⋯⋯z32233313⋯⋯⋯⋯⋯⋯⋯⋯⋯⋯

z891011121314151617181920z32233313323441342355135236613623 The given equation is z3=4. By analysing the table above, we can understand that only z = 12 satisfies the given equation. ∴z=12 is the solution.