Here, Principal (P) Rs 12,000 , Time (T) = 2 years, Rate of interest (R) = 6% p.a
Simple interest
=P×R×T100
=12000×6×2100
=Rs,1,440
Had he borrowed this sum at 6% p.a compound interest then
Compound Interest
=P(1+R100)n−P
=12000(1+6100)2−12000
=12000(1+350)2−12000
=12000(5350)2−12000
=₹13,483.20−₹12,000
=₹1,483.20
Difference in both interest
= ₹1,483.20 - ₹1,440.00 = ₹ 43.20