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Assumed Mean Method

Question 4In ...

Question

Question 4
In the formula $¯ x = a + h (\frac{\sum f_{i} u_{i}}{\sum f_{i}}),$ for finding the mean of grouped frequency distribution $u_{i}$ is equal to
(a) $\frac{x_{i} + a}{h}$
(b) $x_{i} + a$
(c) $\frac{x_{i} + a}{h}$
(a) $\frac{a - x_{i}}{h}$

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Solution

Given, $¯ x = a + h (\frac{\sum f_{i} u_{i}}{\sum f_{i}})$
Above formula is a step deviation formula.
$u_{i} = \frac{x_{i} - a}{h}$

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Similar questions

For finding the mean by using the formula, $¯ x = A + h (\frac{\sum f_{i} u_{i}}{\sum f_{i}}),$ ,we have $u_{i} = ?$

$(a) \frac{(A - x_{i})}{h} (b) \frac{(x_{i} - A)}{h} (c) \frac{(A + x_{i})}{h} (d) h (x_{i} - A)$

x = A + h (\frac{\sum f_{i} u_{i}}{\sum f_{i}})

\frac{(A - x_{i})}{h}

\frac{(x_{i} - A)}{h}

\frac{(A + x_{i})}{h}

h (x_{i} - A)

\bar{X} = a + h (\frac{1}{N} Σ f_{i} u_{i})

u_{i}

\frac{x_{i} + a}{h}

h (x_{i} - a)

\frac{x_{i} - a}{h}

\frac{a - x_{i}}{h}

u_{i} = \frac{x_{i} - 25}{10}, \sum f_{i} u_{i} = 20

\sum f_{i} = 100

¯ ¯ ¯ x

x_{i}

f_{1}

¯ x

\sum (f_{i} x_{i} - ¯ x)

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