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Question 4
P is a point on the bisector of ABC. If the line through P, parallel to BA meet BC at Q, prove that BPQ is an isosceles triangle.

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Solution

Given we have P is a point on the bisector of ABC and draw the line through P parallel to BA and meet BC at Q.

Now, 1=2, As BP is the bisector of B.
and 1=3, Alternate interior angles.
Hence , 2=3 .
So, PQ = BQ. ( Sides opposite to equal angles are equal).
Hence,ΔBPQ is an isosceles triangle.

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