Question 4
The diameter of a roller is 84 cm and its length is 120 cm. It takes 500 complete revolutions to move once over to a level playground. Find the area of the playground in $m^{2}$ ?
$[A s s u m e π = \frac{22}{7}]$

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Solution

A roller is cylindrical shaped.
Height (h) of cylindrical roller = Length of roller = 120 cm
Radius (r) of the circular end of roller
$= (\frac{84}{2}) c m = 42 c m$

CSA of roller
$= 2 π r h$
$= 31680 c m^{2}$

Area of field
$= N u m b e r o f r e v o l u t i o n s \times C S A o f r o l l e r$ $= 500 \times C S A o f r o l l e r$
$= (500 \times 31680) c m^{2} = 15840000 c m^{2} = 1584 m^{2}$

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Similar questions

The diameter of a roller is 84 cm and its length is 120 cm. It takes 500 complete revolutions to move once over to level a playground. Find the area of the playground in $m^{2}$ ? $[A s s u m e π = \frac{22}{7}]$

Q. Question 4
The diameter of a roller is 84 cm and its length is 120 cm. It takes 500 complete revolutions to move once over to a level playground. Find the area of the playground in

m^{2}

[A s s u m e π = \frac{22}{7}]

Q. The diameter of a roller is

84 c m

and its length is

120 c m

. It takes

500

complete revolution to move once over to level a playground. Find the area of the playground in

m^{2}

? [Assume

π = \frac{22}{7}

]

The diameter of a roller is 84 cm and its length is 120 cm. It takes 500 complete revolutions to move once over to level a playground. Find the area of the playground in m²?