Question 4
The distance between the points (0, 5 ) and ( - 5, 0) is:
(A) 5
(B) $5 \sqrt{2}$
(C) $2 \sqrt{5}$
(D) 10

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Solution

$∵ Distance between the points (x_{1}, y_{1}) a n d (x_{2}, y_{2}), d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}} H e r e, x_{1} = 0, y_{1} = 5 a n d x_{2} = - 5, y_{2} = 0 ∴ Distance between P o i n t s (0, 5) a n d (- 5, 0) = \sqrt{(- 5 - 0)^{2} + (0 - 5)^{2}} = \sqrt{25 + 25} = \sqrt{50} = 5 \sqrt{2}$

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Question 9
Zero of the polynomial p(x) = 2x + 5 is

A) $- \frac{2}{5}$
B) $- \frac{5}{2}$
C) $\frac{2}{5}$
D) $\frac{5}{2}$

9 x^{2} - 24 x y + 16 y^{2} - 12 x + 16 y - 12 = 0

2 x + y + 2 z = 8

4 x + 2 y + 4 z + 5 = 0

The ratio in which the line $3 x + 4 y + 2 = 0$ divides the distance between the lines $3 x + 4 y = 0$ and $3 x + 4 y - 5 = 0$ is

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