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Division of a Polynomial by a Polynomial

Question 40In...

Question

Question 40

In the question given below, fill in the blanks to make the statement true:

$(a + b)^{2} - 2 a b =$ _ + _

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Solution

$a^{2} + b^{2}$
We have,
$(a + b)^{2} - 2 a b = a^{2} + b^{2} + 2 a b - 2 a b [∵ (a + b)^{2} = a^{2} + b^{2} + 2 a b] = a^{2} + b^{2}$

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Division of a Polynomial by a Polynomial

Standard VIII Mathematics

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