Question 42If AB - 7C - 102- Where B - 0- C - 0- then A - B - C - 14-

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Standard VIII

Mathematics

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Question 42If...

Question

Question 42

If AB + 7C = 102, Where B $\neq$ 0, C $\neq$ 0, then A + B + C = 14.

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Solution

True
We have, $A B + 7 C______102$
Here, B + C is either 2 or a two - digit number whose one's digit is 2.
If B = C = 1, A = 3 but A + B + C $\neq$ 14
If B = 5, C = 7, A = 2 and A + B + C = 2 + 5 + 7 = 14

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Question 42 If AB + 7C = 102, Where B ≠ 0, C ≠ 0, then A + B + C = 14.

True We have, A B+7 C______ 1 0 2 Here, B + C is either 2 or a two - digit number whose one's digit is 2. If B = C = 1, A = 3 but A + B + C ≠ 14 If B = 5, C = 7, A = 2 and A + B + C = 2 + 5 + 7 = 14

Question 42

If AB + 7C = 102, Where B $\neq$ 0, C $\neq$ 0, then A + B + C = 14.

True
We have, $A B + 7 C______102$
Here, B + C is either 2 or a two - digit number whose one's digit is 2.
If B = C = 1, A = 3 but A + B + C $\neq$ 14
If B = 5, C = 7, A = 2 and A + B + C = 2 + 5 + 7 = 14