CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Letters for Digits

Question 42If...

Question

Question 42

If AB + 7C = 102, Where B $\neq$ 0, C $\neq$ 0, then A + B + C = 14.

Open in App

Solution

True
We have, $A B + 7 C______102$
Here, B + C is either 2 or a two - digit number whose one's digit is 2.
If B = C = 1, A = 3 but A + B + C $\neq$ 14
If B = 5, C = 7, A = 2 and A + B + C = 2 + 5 + 7 = 14

Suggest Corrections

thumbs-up

0

Similar questions

Given $a x^{2}$ $+$ $b x$ $+ c$ $\geq 0$ , $b x^{2} + c x + a \geq 0$ , $c x^{2} + a x + b \geq 0$ where $a \neq b \neq c$ and $a, b, c ϵ R$ . Now $\frac{a^{2} + b^{2} + c^{2}}{a b + b c + c a}$ cannot take the value(s)

x^{2} - (a + b + c) x + (a b + b c + c a) = 0

has imaginary roots, where

a, b, c \in R^{+},

\sqrt{a}, \sqrt{b}, \sqrt{c}

Q. If both the roots of

a x^{2} + b x + c = 0

are real, positive and distinct, then
(where

Δ = b^{2} - 4 a x

a, b, c

are real distinct numbers satisfying the condition

a + b + c = 0

, then the roots of the quadratic equation

3 a x^{2} + 5 b x + 7 c = 0

tan A, tan B

are the roots of the quadratic

a b x^{2} - c^{2} x + a b = 0

a, b, c

are the sides of a triangle, then prove

cos C = 0

View More

Join BYJU'S Learning Program

explore_more_icon

Explore more

Letters for Digits

Standard VIII Mathematics

Join BYJU'S Learning Program

CrossIcon