Question 45

In the following question, fill in the blanks to make the statements true.

$[2^{- 1} + 3^{- 1} + 4^{- 1}]^{0} =$ ___

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Solution

Using law of exponent $a^{0} = 1 ∴ [2^{- 1} + 3^{- 1} + 4^{- 1}]^{0} = 1$

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