Question

Question 48
PQRS is a trapezium in which $PQ\parallel SR$ and $\angle P={130}^{\circ },\angle Q={110}^{\circ }$. Then, $\angle R$ is equal to
a) ${70}^{\circ }$
b) ${50}^{\circ }$
c) ${65}^{\circ }$
d) ${55}^{\circ }$

Answer 1

Since, PQRS is a trapezium and $PQ\parallel SR$.
$\therefore \angle Q+\angle R={180}^{\circ }$ [$\because$ angles between the pair of parallel sides are supplementary]
$\Rightarrow \angle R={180}^{\circ }-{110}^{\circ }={70}^{\circ }$