Question

Question 48

Which pair of ratios are equal? and why?

(i) $\frac{2}{3},\frac{4}{6}$
(ii) $\frac{8}{4},\frac{2}{1}$
(iii) $\frac{4}{5},\frac{12}{20}$

Answer 1

Checking all the options one by one, we get:

(i) $\frac{2}{3},\frac{4}{6}$

Simplest form of $\frac{4}{6}=\frac{2}{3}$
Simplest form of $\frac{2}{3}=\frac{2}{3}$
Since, the simplest form of both the ratios are equal, hence $\frac{2}{3}$ and $\frac{4}{6}$ are equal ratios.

(ii) $\frac{8}{4},\frac{2}{1}$
Simplest form of $\frac{8}{4}=\frac{2}{1}$
Simplest form of $\frac{2}{1}=\frac{2}{1}$

Since, the simplest form of both the ratios are equal, hence $\frac{8}{1}$ and $\frac{2}{1}$ are equal ratios.

(iii) $\frac{4}{5},\frac{12}{20}$
Simplest form of $\frac{12}{20}=\frac{3}{5}$
Since, $\frac{4}{5}\ne \frac{3}{5}$
Hence, $\frac{4}{5}$ and $\frac{12}{20}$ ratios are not equal.