Question

Question 5
Construct a $\Delta ABC$ in which BC =5cm, $\angle B={60}^{\circ }$ and AC + AB = 7.5cm.

Answer 1

Given, in $\Delta ABC,BC=5cm,\angle B={60}^{\circ }$ and AC + AB = 7.5cm. to

Steps to construct the triangle ABC
(i) Draw the base BC = 5cm.
(ii) At the point B make an $\angle XBC={60}^{\circ }$
(iii) Cut a line segment BD equal to AB + AC= 7.5cm on the ray BE.
(iv) Join DC.
(v) Make an $\angle DCY=\angle BDC$
(vi) Let CY intersect BE at A. Then, $\Delta ABC$ is the required triangle.