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Question

Question 5(d)
Substract: 3a(a+b+c)2b(ab+c)from 4c(a+b+c).


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Solution

4c(a+b+c)[3a(a+b+c)2b(ab+c)]
=4ac+4bc+4c2[3a2+3ab+3ac2ab+2b22bc]
=4ac+4bc+4c2[3a2+2b2+3ab2bc+3ac2ab]
=4ac+4bc+4c2[3a2+2b2+ab+3ac2bc]
=4ac+4bc+4c23a22b2ab3ac+2bc
=3a22b2+4c2ab+4bc+2bc4ac3ac
=3a22b2+4c2ab+6bc7ac


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