Question 5 iRationalize the denominator of 1-7 -

Name: NCERT - Grade 09 - Mathematics - Number Systems - Q23_1
Uploaded: 2022-07-04T10:36:42+05:30
Description: 1/√(7) Multiplying √(7) to nbsp;numerator and denominator, we get, =1 ×√(7)/√(7)×√(7) =√(7)/7 ...

1/√(7) Multiplying √(7) to nbsp;numerator and denominator, we get, =1 ×√(7)/√(7)×√(7) =√(7)/7 ...

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Standard IX

Mathematics

Rationalisation of Denominator

Question 5 iR...

Question

Question 5 (i)
Rationalize the denominator of $\frac{1}{\sqrt{7}}$ .

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Solution

$\frac{1}{\sqrt{7}}$

Multiplying $\sqrt{7}$ to numerator and denominator, we get,

$= \frac{1 \times \sqrt{7}}{\sqrt{7} \times \sqrt{7}}$

$= \frac{\sqrt{7}}{7}$

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Similar questions

Question 5 (ii)
Rationalize the denominator of :
$\frac{1}{(\sqrt{7} - \sqrt{6})}$ .

Question 5 (iv)
Rationalize the denominators of the following:

$\frac{1}{(\sqrt{7} - 2)}$

Question 5 (i)
Rationalize the denominator of $\frac{1}{\sqrt{7}}$ .

Question 5 (ii)
Rationalize the denominator of :
$\frac{1}{(\sqrt{7} - \sqrt{6})}$ .

Question 5 (iv)
Rationalize the denominators of the following:

$\frac{1}{(\sqrt{7} - 2)}$

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Rationalisation of Denominator

Standard IX Mathematics

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Question 5 (i) Rationalize the denominator of 1√7 .

1√7 Multiplying √7 to numerator and denominator, we get, =1×√7√7×√7 =√77

Question 5 (i)
Rationalize the denominator of $\frac{1}{\sqrt{7}}$ .

$\frac{1}{\sqrt{7}}$

Multiplying $\sqrt{7}$ to numerator and denominator, we get,

$= \frac{1 \times \sqrt{7}}{\sqrt{7} \times \sqrt{7}}$

$= \frac{\sqrt{7}}{7}$