Question 5If 90a 325 kmb 350 kmc 350 md 325 m

Name: EXEMP - Grade 08 - Mathematics - Comparing Quantities - Q5
Uploaded: 2022-07-04T10:36:42+05:30
Description: We have, 90 ⇒ 90/100× x =315 ⇒ x=315 × 100/90 =315 × 10/9=350 ⇒ x = 350 km ...

We have, 90 ⇒ 90/100× x =315 ⇒ x=315 × 100/90 =315 × 10/9=350 ⇒ x = 350 km ...

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Standard VI

Mathematics

Dividing a 2D Object into Equal Parts

Question 5If ...

Question

Question 5

If 90% of x is 315 km, then the value of x is
(a) 325 km
(b) 350 km
(c) 350 m
(d) 325 m

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Solution

We have, 90% of x = 315 km
$\Rightarrow \frac{90}{100} \times x = 315 \Rightarrow x = \frac{315 \times 100}{90} = \frac{315 \times 10}{9} = 350 \Rightarrow x = 350 k m$

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Dividing a 2D Object into Equal Parts

Standard VI Mathematics

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Question 5 If 90% of x is 315 km, then the value of x is (a) 325 km (b) 350 km (c) 350 m (d) 325 m

We have, 90% of x = 315 km ⇒ 90100×x=315⇒ x=315×10090=315×109=350⇒x=350 km

Question 5

If 90% of x is 315 km, then the value of x is
(a) 325 km
(b) 350 km
(c) 350 m
(d) 325 m

We have, 90% of x = 315 km
$\Rightarrow \frac{90}{100} \times x = 315 \Rightarrow x = \frac{315 \times 100}{90} = \frac{315 \times 10}{9} = 350 \Rightarrow x = 350 k m$