Question 5
If m is the mid-point and l is the upper class limit of a class in a continuous frequency distribution, then the lower class limit of the class is:
A) 2m + I
B) 2m - l
C) M - l
D) M - 2I
Let x and y be the lower and upper class limit of a continuous frequency distribution.
Now, mid - point of a class
=x+y2=m [given]
⇒x+y=2m⇒x+l=2m
[∵y = l = upper class limit (given)]
⇒x=2m−l
Hence,the lower class limit of the class is 2m – l.