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Algebraic Identities

Question 5If ...

Question

Question 5
If $p (x) = x^{2} - 2 \sqrt{2} x + 1$ , then $p (2 \sqrt{2})$ is equal to

A) 0
B) 1
C) $4 \sqrt{2}$
D) $8 \sqrt{2} + 1$

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Solution

$p (x) = x^{2} - 2 \sqrt{2} x + 1$
On putting x = $2 \sqrt{2}$
$p (2 \sqrt{2}) = (2 \sqrt{2})^{2} - (2 \sqrt{2}) (2 \sqrt{2}) + 1$
$= 8 - 8 + 1 = 1$
So,the answer is B.

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Algebraic Identities

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