If we subtract −3x2y2 from x2y2, then we get
a) −4x2y2
b) −2x2y2
c) 2x2y2
d) 4x2y2
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Solution
d) 4x2y2 →Given, monomials are −3x2y2 and x2y2. Now, we have to subtract the first one from the second one.
i.e. x2y2−(−3x2y2)=x2y2−(−3)x2y2=x2y2+3x2y2=(1+3)x2y2=4x2y2