Question 5 (ii)
Prove the following identities, where the angles involved are acute angles for which the expressions are defined.
(ii) cosA(1+sinA)+(1+sinA)cosA=2secA
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Solution
(ii) cosA(1+sinA)+(1+sinA)cosA=2secA L.H.S.=cosA(1+sinA)+(1+sinA)cosA=[cos2A+(1+sinA)2](1+sinA)cosA=(cos2A+sin2A+1+2sinA)(1+sinA)cosA=(1+1+2sinA)(1+sinA)cosA=(2+2sinA)(1+sinA)cosA=2(1+sinA)(1+sinA)cosA=2cosA=2secA=R.H.S.