Question 5 iiRationalize the denominator of -1-7-6 -

1/√(7) √(6)=1(√(7)+√(6))/(√(7) √(6))(√(7)+√(6)) nbsp; [Multiplying numerator and denominator with (√(7)+√(6))] =√(7)+√(6)/(√(7))^2 (√(6))^2=√(7)+√(6)/1=√(7) ...

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Standard IX

Mathematics

Rationalisation of Denominator

Question 5 ii...

Question

Question 5 (ii)
Rationalize the denominator of :
$\frac{1}{(\sqrt{7} - \sqrt{6})}$ .

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Solution

$\frac{1}{\sqrt{7} - \sqrt{6}} = \frac{1 (\sqrt{7} + \sqrt{6})}{(\sqrt{7} - \sqrt{6}) (\sqrt{7} + \sqrt{6})} [M u l t i p l y i n g n u m e r a t o r a n d d e n o m i n a t o r w i t h (\sqrt{7} + \sqrt{6})] = \frac{\sqrt{7} + \sqrt{6}}{(\sqrt{7})^{2} - (\sqrt{6})^{2}} = \frac{\sqrt{7} + \sqrt{6}}{1} = \sqrt{7} + \sqrt{6}$

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Question 5 (ii)
Rationalize the denominator of :
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Rationalize the denominator of $\frac{1}{\sqrt{7}}$ .

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Rationalize the denominator of $\frac{1}{\sqrt{7}}$ .

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Rationalisation of Denominator

Standard IX Mathematics

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Question 5 (ii) Rationalize the denominator of : 1(√7−√6) .

1√7−√6=1(√7+√6)(√7−√6)(√7+√6)[Multiplying numerator and denominator with (√7+√6)]=√7+√6(√7)2−(√6)2=√7+√61=√7+√6

Question 5 (ii)
Rationalize the denominator of :
$\frac{1}{(\sqrt{7} - \sqrt{6})}$ .