Question 5 (iv)
Rationalize the denominators of the following:

$\frac{1}{(\sqrt{7} - 2)}$

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Solution

Multiply and divide with $(\sqrt{7} + 2) .$
$\frac{1}{\sqrt{7} - 2} = \frac{1 (\sqrt{7} + 2)}{(\sqrt{7} - 2) (\sqrt{7} + 2)} = \frac{\sqrt{7} + 2}{(\sqrt{7})^{2} - (2)^{2}} = \frac{\sqrt{7} + 2}{7 - 4} = \frac{\sqrt{7} + 2}{3}$

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Question 5 (iii)
Rationalize the denominators of the following:

$\frac{1}{(\sqrt{5} + \sqrt{2})}$

Question 5 (iv)
Rationalize the denominators of the following:

$\frac{1}{(\sqrt{7} - 2)}$

Question 5 (ii)
Rationalize the denominator of :
$\frac{1}{(\sqrt{7} - \sqrt{6})}$ .

Question 5 (i)
Rationalize the denominator of $\frac{1}{\sqrt{7}}$ .

\frac{1}{\sqrt{7}}

\frac{1}{\sqrt{7} - \sqrt{6}}

\frac{1}{\sqrt{5} + \sqrt{2}}

\frac{1}{\sqrt{7} - 2}

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