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Question

Question 5(iv)
Show that:
(4pq+3q)2(4pq3q)2=48pq2

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Solution

L.H.S = (4pq+3q)2(4pq3q)2
=(4pq)2+2×4pq×3q+(3q)2[(4pq)22×4pq×3q+(3q)2]
[Using identities (a+b)2=a2+2ab+b2 and (ab)2=a22ab+b2]
=16p2q2+24pq2+9q2[16p2q224pq2+9q2] =16p2q2+24pq2+9q216p2q2+24pq29q2
=48pq2
=R.H.S

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