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Predicting Last Digit of an Exponent

Question 5Obs...

Question

Question 5
Observe the following pattern and supply the missing numbers.

$11^{2} = 121 101^{2} = 10201 10101^{2} = 102030201 1010101^{2} = . . . . . . . . . . . . . . . . . . . . . . . . . .^{2} = 10203040504030201$

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Solution

$11^{2} = 121 101^{2} = 10201 10101^{2} = 102030201 1010101^{2} = 1020304030201 101010101^{2} = 10203040504030201$

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Question 5
Observe the following pattern and supply the missing numbers.

$11^{2} = 121 101^{2} = 10201 10101^{2} = 102030201 1010101^{2} = . . . . . . . . . . . . . . . . . . . . . . . . . .^{2} = 10203040504030201$

11^{2} = 121

101^{2} = 10201

10101^{2} = 102030201

1010101^{2} = . . . . . . . . . . . . . . . .

. . . . . . . . . . . . . .^{2} = 10203040504030201

11^{2} = 121

101^{2} = 10201

10101^{2} = 102030201

1010101^{2} = 1020304030201

. . . . . . . . . . . . .^{2} = 10203040504030201

Question 4
Observe the following pattern and find the missing digits.

$11^{2} = 121 101^{2} = 10201 1001^{2} = 1002001 100001^{2} = 1....2....1 10000002^{2} = 1...........$

11^{2} = 121

101^{2} = 10201

10101^{2} = 102030201

1010101^{2} = . . . . . . . . . . . . . . . . . . . . . .

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