Question

Question 5
The measures of two adjacent angles of a parallelogram are in the ratio 3:2. Find the measure of each of the angles of the parallelogram.

Answer 1

Let two adjacent angles be 3x and 2x.
Since the adjacent angles in a parallelogram are supplementary,
$3x+2x={180}^{\circ }\Rightarrow 5x={180}^{\circ }\Rightarrow x=\frac{{180}^{\circ }}{5}={36}^{\circ }\therefore Oneangle=3x=3\times {36}^{\circ }={108}^{\circ }Otherangle=2x=2\times {36}^{\circ }={72}^{\circ }$