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Question 5
What length of tarpaulin 3 m wide will be required to make a conical tent of height 8 m and base radius 6m? Assume that the extra length of material that will be required for stitching margins and wastage in cutting is approximately 20 cm.[Use π=3.14]

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Solution

Height (h) of the conical tent = 8 m
Radius (r) of base of the tent= 6 m
Slant height (l) of the tent =r2+h2
=(62+82)m=(100)m=10 m
CSA of conical tent = πrl
=(3.14×6×10)m2
=188.4 m2
Let the length of tarpaulin sheet required be l.
As 20 cm will be wasted, the effective length will be ( l – 0.2 m).
Breadth of tarpaulin = 3 m
Area of sheet = CSA of the tent
[(l0.2)×3]m2=188.4 m2
l – 0.2 m = 62.8 m
l = 63 m
therefore, the length of the required tarpaulin sheet will be 63 m.

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