Height (h) of the conical tent = 8 m
Radius (r) of base of the tent= 6 m
Slant height (l) of the tent =√r2+h2
=(√62+82)m=(√100)m=10 m
CSA of conical tent = πrl
=(3.14×6×10)m2
=188.4 m2
Let the length of tarpaulin sheet required be l.
As 20 cm will be wasted, the effective length will be ( l – 0.2 m).
Breadth of tarpaulin = 3 m
Area of sheet = CSA of the tent
[(l−0.2)×3]m2=188.4 m2
l – 0.2 m = 62.8 m
l = 63 m
therefore, the length of the required tarpaulin sheet will be 63 m.