Question 52
Two cylinders of same volume have their radii in the ratio 1 : 6. Then, ratio of their heights is
36 : 1
Let r1, r2 be the radii and h1, h2 be the heights of two cylinders.
Given, r1r2=16
Now, according to the question,
πr21h1=πr22h2 [∵ volume of cylinder =πr2h]
⇒r21r22=h2h1⇒(r1r2)2=h2h1⇒(16)2=h2h1⇒136=h2h1
or h1h2=361
or h1:h2=36:1