Question 54
The sum of areas of two squares with sides 4a and 4b is ___
16(a2+b2) ∵ Area of the square whose one side is 4a=(4a)2=16a2 Area of the square with side 4b=(4b)2=16b2 ∴ Sum of areas = 16a2+16b2=16(a2+b2)
Two squares have sides x cm and (x+4) cm. The sum of their areas is 656cm2. Find the sides of the squares.