Question

Question 56

Find the value of the letters in the following question:

$AB\times 6\_\_\_\_\_\_\_\_C68$

Answer 1

We have, $AB\times 6\_\_\_\_\_\_\_\_C68$ and B - A =1
Here, $6\times B$ is a number, whose unit's whose digit is 8. Therefore, the possible values of B are 3 and 8.
If B = 3, then A $\times 6+1=C6$ which is not possible for any value of A between 0 to 9.
$\therefore$ B = 8 and then A = 7
The values of A and B also satisfies the given condition i.e. 8 - 7 = 1.
If A = 7, then $7\times 6÷4=C646=C6\therefore C=4$
Hence, A = 7, B = 8 and C = 4