Question 6
ABC is an equilateral triangle of side 2a. Find each of its altitudes.
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Solution
Given ABC is an equilateral triangle of side 2a. DrawAD⊥BC.
In ΔADB and ΔADC, we have
AB = AC [Given]
AD = AD [Common] ∠ADB=∠ADC [each angle equal to 90∘]
Therefore, ΔADB≅ΔADC by RHS congruency rule.
Hence, BD = DC [by CPCT]
In right angled ΔADB, AB2=AD2+BD2 ⇒(2a)2=AD2+a2 ⇒AD2=4a2−a2 ⇒AD2=3a2 ⇒AD=√3a