Question

Question 6
If in two $\Delta DEFand\Delta PQR,\angle D=\angle Qand\angle R=\angle E$, then which of the following is not true?

(A) $\frac{EF}{PR}=\frac{DF}{PQ}$
(B) $\frac{DE}{PQ}=\frac{EF}{RP}$
(C) $\frac{DE}{QR}=\frac{DF}{PQ}$
​​​​​​(D) $\frac{EF}{RP}=\frac{DE}{QR}$

Answer 1

(B) $\frac{DE}{PQ}=\frac{EF}{RP}$

Given, in $\Delta DEFand\Delta PQR,\angle D=\angle Q,\angle R=\angle E$

$\therefore \Delta DEF\sim \Delta QRP$ [ by AAA similarity criterion ]
$\Rightarrow \angle F=\angle P$ [ corresponding angles of similar triangles ]
$\therefore \frac{DF}{QP}=\frac{ED}{RQ}=\frac{EF}{PR}$