Question 6 (ii)
In the given figure, diagonals AC and BD of quadrilateral ABCD intersect at O such thatOB = OD. If AB = CD, then show that:
(ii) ar(DCB) = ar(ACB)
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Solution
Let us draw DN⊥AC and BM⊥AC.
(ii) We obtained,
Area (ΔDOC)=Area(ΔAOB)
i.e Area(ΔDOC)+Area(ΔOCB)=Area(ΔAOB)+Area(ΔOCB)
(Adding Area (ΔOCB) to both sides) ⇒Area(ΔDCB)=Area(ΔACB)