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Question 6iiU...

Question

Question 6(ii)
Using identities, evaluate:
$99^{2}$

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Solution

$99^{2} = (100 - 1)^{2} = (100)^{2} - 2 \times 100 \times 1 + (1)^{2}$
$[U s i n g i d e n t i t y (a - b)^{2} = a^{2} - 2 a b + b^{2}]$
$= 10000 - 200 + 1 = 9801$

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