wiz-icon
MyQuestionIcon
MyQuestionIcon
3
You visited us 3 times! Enjoying our articles? Unlock Full Access!
Question

Question 6(iii)
Using identities, evaluate:
1022

Open in App
Solution

1022=(100+2)2=(100)2+2×100×2+(2)2
[Using identity (ab)2=a22ab+b2]
=10000+400+4=10404

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon