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Byju's Answer
Standard VII
Mathematics
Like Terms
Question 6Lik...
Question
Question 6
Like term as
4
m
3
n
2
is
a)
4
m
2
n
2
b)
−
6
m
3
n
2
c)
6
p
m
3
n
2
d)
4
m
3
n
2
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Solution
b)
−
6
m
3
n
2
→
We know that, the like terms contain the same literal factor. So, the like term as
4
m
3
n
2
is
−
6
m
3
n
2
, as it contains the same literal factor
m
3
n
2
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1
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Question 15
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Standard VII Mathematics
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