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Byju's Answer
Standard IX
Mathematics
Real Numbers
Question 6m-m...
Question
Question 6
m
−
m
−
1
2
=
1
−
m
−
2
3
Open in App
Solution
m
−
m
−
1
2
=
1
−
m
−
2
3
⇒
2
m
−
m
+
1
2
=
3
−
m
+
2
3
⇒
m
+
1
2
=
5
−
m
3
⇒
3
(
m
+
1
)
=
2
(
5
−
m
)
⇒
3
m
+
3
=
10
−
2
m
⇒
3
m
+
2
m
=
10
−
3
⇒
5
m
=
7
⇒
m
=
7
5
⇒
Check:
⇒
7
5
−
7
5
−
1
2
= 1-
7
5
−
2
3
⇒
7
5
−
7
−
5
5
2
=
1
−
7
−
10
5
3
⇒
7
5
−
2
5
×
2
=
1
−
−
3
5
×
3
⇒
7
5
−
1
5
=
1
+
1
5
⇒
7
−
1
5
=
5
+
1
5
⇒
6
5
=
6
5
⇒
L
.
H
.
S
.
=
R
.
H
.
S
Therefore, it is correct
Suggest Corrections
3
Similar questions
Q.
Question 6
m
−
m
−
1
2
=
1
−
m
−
2
3
Q.
If
6
m
2
+
2
m
2
=
7
, then
m
=
±
√
2
3
,
±
1
√
2
.
Q.
Question 75
Solve the following:
m
−
m
−
1
2
=
1
−
m
−
2
3
Q.
Question 75
Solve the following:
m
−
m
−
1
2
=
1
−
m
−
2
3
Q.
Simplify :
5
m
3
−
m
+
6
m
2
−
(
3
m
2
−
2
+
m
)
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