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Byju's Answer
Standard VI
Biology
Pond Habitat
Question 6Wri...
Question
Question 6
Write ‘True’ or ‘False’ and justify your answer in each of the following:
(
t
a
n
θ
+
2
)
(
2
t
a
n
θ
+
1
)
=
5
t
a
n
θ
+
s
e
c
2
θ
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Solution
The statement is true.
LHS
=
(
t
a
n
θ
+
2
)
(
2
t
a
n
θ
+
1
)
=
2
t
a
n
2
θ
+
4
t
a
n
θ
+
t
a
n
θ
+
2
=
2
(
s
e
c
2
θ
−
1
)
+
5
tan
θ
+
2
⌊
∵
s
e
c
2
θ
−
t
a
n
2
θ
=
1
⌋
=
2
s
e
c
2
θ
+
5
t
a
n
θ
=
R
H
S
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