Question 60
Solve the following:
4t-3-(3t+1)=5t-4
Given, 4t-3-(3t+1)=5t-4 ⇒4t−3−3t−1=5t−4⇒t−4=5t−4⇒t−5t=−4+4⇒−4t=0⇒−4t−4=0−4∴t=0
Question 68
3t+54−1=4t−35
When we divide 3t4+5t3−7t2+2t+2 by t2+3t+1, we get 3t2−4t+2 as quotient.
Question 82 (iv)
Subtract
3t4−4t3+2t2−6t+6 from−4t4+8t3−4t2−2t+11