Question

Question 61

In the following question, fill in the blanks to make the statements true.

The value of $[2^{-1}\times 3^{-1}{]}^{-1}$ is ___

Answer 1

Using law of exponents,$a^{-m}=\frac{1}{a^m}\therefore [2^{-1}\times 3^{-1}{]}^{-1}={(\frac{1}{2}\times \frac{1}{3})}^{-1}={\left(\frac{1}{6}\right)}^{-1}=6$
hence $[2^{-1}\times 3^{-1}{]}^{-1}=6$