Question 68
Solve the following:
3t+54−1=4t−35
Given, 3t+54−1=4t−35⇒3t+5−44=4t−35⇒5(3t+1)=4(4t−3)⇒15t+5=16t−12⇒15t−16t=−12−5⇒−t=−17⇒−t−1=−17−1∴t=17
Question 60
4t-3-(3t+1)=5t-4
Question 82 (iv)
Subtract
3t4−4t3+2t2−6t+6 from−4t4+8t3−4t2−2t+11