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Linear Equations in Three Variable

Question 69So...

Question

Question 69

Solve the following:

$\frac{2 y - 3}{4} - \frac{3 y - 5}{2} = y + \frac{3}{4}$

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Solution

Given, $\frac{2 y - 3}{4} - \frac{3 y - 5}{2} = y + \frac{3}{4} \Rightarrow \frac{2 y - 3 - 2 (3 y - 5)}{4} = \frac{4 y + 3}{4} \Rightarrow 2 y - 3 - 6 y + 10 = 4 y + 3 \Rightarrow - 4 y + 7 = 4 y + 3 \Rightarrow - 8 y = - 4 \Rightarrow \frac{- 8 y}{- 8} = \frac{- 4}{- 8} ∴ y = \frac{1}{2}$

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Linear Equations in Three Variable

Standard X Mathematics

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