3(t 3)=5(2t+1) ⇒ 3t 9 =10t+5 ⇒ 3t 10t=5+9 nbsp; nbsp; ⇒ 7t=14 ⇒ t=14/ 7 nbsp; ⇒ t= 2 To check: 3(t 3)=5(2t+1) nbsp; ⇒ 3( 2 3)=5(2 × ( 2)+1) ⇒ 3 × 5= ...

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Standard VI

Mathematics

Formation of an Expression

Question 73t-...

Question

Question 7
$3 (t - 3) = 5 (2 t + 1)$

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Solution

$3 (t - 3) = 5 (2 t + 1) \Rightarrow 3 t - 9 = 10 t + 5$
$\Rightarrow 3 t - 10 t = 5 + 9 \Rightarrow - 7 t = 14$
$\Rightarrow t = \frac{14}{- 7} \Rightarrow t = - 2$

To check:

$3 (t - 3) = 5 (2 t + 1) \Rightarrow 3 (- 2 - 3) = 5 (2 \times (- 2) + 1)$
$\Rightarrow 3 \times - 5 = 5 (- 4 + 1) \Rightarrow - 15 = 5 \times (- 3)$
$\Rightarrow - 15 = - 15$
$\Rightarrow L . H . S . = R . H . S$ .

Therefore, it is correct.

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Similar questions

Q. Question 7

3 (t - 3) = 5 (2 t + 1)

Q. Solve the following equation:

3 (t - 3) = 5 (2 t - 1)

Q. Solve the linear equation:

3 (t - 3) = 5 (2 t + 1)

Solve the following linear equation.

3 (t - 3) = 5 (2 t + 1)

Simplify and solve the equation:

3 (t - 3) = 5 (2 t + 1)

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Formation of an Expression

Standard VI Mathematics

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Question 7 3(t−3)=5(2t+1)

3(t−3)=5(2t+1)⇒3t−9=10t+5 ⇒3t−10t=5+9⇒−7t=14 ⇒t=14−7⇒t=−2 To check: 3(t−3)=5(2t+1)⇒3(−2−3)=5(2×(−2)+1) ⇒3×−5=5(−4+1)⇒−15=5×(−3) ⇒−15=−15 ⇒L.H.S.=R.H.S. Therefore, it is correct.

Question 7
$3 (t - 3) = 5 (2 t + 1)$