Question

Question 7
$3(t-3)=5(2t+1)$

Answer 1

$3(t-3)=5(2t+1)\Rightarrow 3t-9=10t+5$
$\Rightarrow 3t-10t=5+9\Rightarrow -7t=14$
$\Rightarrow t=\frac{14}{-7}\Rightarrow t=-2$

To check:

$3(t-3)=5(2t+1)\Rightarrow 3(-2-3)=5(2\times (-2)+1)$
$\Rightarrow 3\times -5=5(-4+1)\Rightarrow -15=5\times (-3)$
$\Rightarrow -15=-15$
$\Rightarrow L.H.S.=R.H.S$.

Therefore, it is correct.