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Question

Question 7
D is any point on side AC of a ΔABC with AB = AC. Show that CD < BD.

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Solution

Given: In ΔABC, AB = AC and D is any point of side AC.


In ΔABC AC = AB [given]
ABC=ACB...(i)
[angles opposite to equal sides are equal]

In ΔABC, ABC>DBC [since, DBC is a part of B]
ACB>DBC [From Eq.(i)]
BD>CD or CD<BD [side opposite to greater angle is longer]

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