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Question 7ivU...

Question

Question 7(iv)
Using $a^{2} - b^{2} = (a + b) (a - b),$ find
${12.1}^{2} - {7.9}^{2}$

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Solution

${12.1}^{2} - {7.9}^{2} = (12.1 + 7.9) (12.1 - 7.9)$
$[U s i n g i d e n t i t y (a - b) (a + b) = a^{2} - b^{2}]$
$= 20.0 \times 4.2 = 84.0 = 84$

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Similar questions

a^{2} - b^{2} = (a + b) (a - b),

{12.1}^{2} - {7.9}^{2}

a^{2} - b^{2} = (a + b) (a - b)

{12.1}^{2} - {7.9}^{2}

a^{2} - b^{2} = (a + b) (a - b)

(i) 153^{2} - 147^{2} (i i) {12.1}^{2} - {7.9}^{2}

Q. Question 7(iii)
Using

a^{2} - b^{2} = (a + b) (a - b),

153^{3} - 147^{2}

Q. Question 7(ii)
Using

a^{2} - b^{2} = (a + b) (a - b),

(1.02)^{2} - (0.98)^{2}

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