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Question 7
The table below shows the salaries of 280 persons.
Salary(in Rs.thousand) Number of persons 510 49 1015 133 1520 63 2025 15 2530 6 3035 7 3540 4 4045 2 4550 1
Calculate the median and mode of the data.

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Solution

First, we construct a cumulative frequency table
Salary (in Rs.thousand)Number of persons(fi)Cumulative frequency(cf) 510 49=f149=(cf ) 1015 fm=133=f133+49=182 1520 63=f2182+63=245 2025 15245+15=260 2530 6260+6=266 3035 7266+7=273 3540 4273+4=277 4045 2277+2=279 4550 1279+1=280 N=280
N2=2802=140
(i) Here, median class is 10-15, because 140 lies in it.
Lower limit(l)=10, Frequency(f)=133,
Cumulative frequency cf=49 and class width(h)=5
Median=l+(N2cf)f×h=10+(14049)133×5=10+91×5133=10+455133=10+3.421=Rs.13.421(in thousand)=13.421×1000=Rs.13421
(ii) Here, the highest frequency is 133, which lies in the interval 10-15, called modal class.
Lower limit(l)=10, class width(h)=5, fm=133, f1=49 and f2=63.
Mode=l+(fmf12fmf1f2×h)=10+{13349(2×133)4963}×5=10+84×5266112=10+84×5154=10+2.727=Rs.12.727(in thousand)=12.727×1000=Rs.12727
Hence, the median and modal salary are Rs. 13421 and Rs. 12727, respectively.

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