Question 72

In 2007-08, the number of students appeared for Class X examination was 105332 and in 2008-09 the number was 116054. If 88151 students pass the examination in 2007-08 and 103804 students in 2008-09. What is the increase or decrease in pass percentage in class X result?

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Solution

Number of students appeared in 2007-08 = 105332
Number of students appeared in 2008-09 = 116054
Number of students passed in 2007-08 = 88151
Number of students passed in 2008-09 = 103804
Passed percentage of students in 2007-08
$= \frac{N u m b e r o f s t u d e n t s p a s s e d i n 2007 - 08}{N u m b e r o f s t u d e n t s a p p e a r e d i n 2007 - 08} \times 100 = \frac{88151}{105332} \times 100 = \frac{8815100}{105332} = 83.68 %$
Passed percentage of students in 2008-09
$= \frac{N u m b e r o f s t u d e n t s p a s s e d i n 2008 - 09}{N u m b e r o f s t u d e n t s a p p e a r e d i n 2008 - 09} \times 100 = \frac{103804}{116054} \times 100 = \frac{10380400}{116054} = 89.44 %$
$∴$ Increase in percentage = 89.44 - 83.68 = 5.76%

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Question 72

In 2007-08, the number of students appeared for Class X examination was 105332 and in 2008-09 the number was 116054. If 88151 students pass the examination in 2007-08 and 103804 students in 2008-09. What is the increase or decrease in pass percentage in class X result?

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