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Question
Question 75
Solve the following:
m−m−12=1−m−23
Question 75
Solve the following:
m−m−12=1−m−23
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Solution
Given, m−m−12=1−m−23
⇒2m−(m−1)2=3−(m−2)3⇒3(2m−m+1)=2(3−m+2)⇒3(m+1)=2(5−m)⇒3m+3=10−2m⇒5m=7∴m=75
Given, m−m−12=1−m−23
⇒2m−(m−1)2=3−(m−2)3⇒3(2m−m+1)=2(3−m+2)⇒3(m+1)=2(5−m)⇒3m+3=10−2m⇒5m=7∴m=75
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