Question 76

Solve the following:

4(3p+2)-5(6p-1)=2(p-8)-6(7p-4)

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Solution

Given, 4(3p+2)-5(6p-1)=2(p-8)-6(7p-4)
$\Rightarrow 12 p + 8 - 30 p + 5 = 2 p - 16 - 42 p + 24 \Rightarrow - 18 p + 13 = - 40 p + 8 \Rightarrow - 18 p + 40 p = 8 - 13 \Rightarrow 22 p = - 5 \Rightarrow \frac{22 p}{22} = \frac{- 5}{22} ∴ p = \frac{- 5}{22}$

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Factors of $49 p^{2} - 36$ are:

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Question 76

Solve the following:

4(3p+2)-5(6p-1)=2(p-8)-6(7p-4)

a^{2} - 2 a b + b^{2} = (a - b)^{2}

p^{2} - 2 p + 1

Using properties of determinants prove the following questions.

$∣ ∣ ∣ ∣ \begin{matrix} 1 & 1 + p & 1 + p + q 2 & 3 + 2 p & 4 + 3 p + 2 q 3 & 6 + 3 p & 10 + 6 p + 3 q \end{matrix} ∣ ∣ ∣ ∣ = 1$

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